opietaylor93#81905
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opietaylor93#81905
commented
Hello, I have a mathematics and probability masters degree and find this sort of stuff fascinating. I work with major platforms and machinery that specializes in randomizing, odds and probability. While most stuff does seem random and by “chance”; complex calculations allow us to understand that with enough rinse and repeat (for laymen's terms) proves that there is always some sort of pattern associated with numbers. For example, I have done some calculations that are correct (you can check yourself) that prove that the shuffling system in MTG Arena is not truly a chance factor. Here is what I found.
I have played hundreds of matches in Arena, paid hundreds of dollars for gems to play in limited events and been a great reoccurring customer to MTGA. Here is the equation I used which is tried and true and also correct without any errors:
This applies to any stretch of lands you pull off the top with or without a shuffle, The math stays the same. I personally experience this problem in about 45-60% (this is out of 100 games at a time that I studied) of my games which should be enough proof that this is obviously a money grab via Wizards of the Coast.
First we calculate the odds that 5 specific consecutive cards are all lands. (My ratio is 6.1 lands 57% of the time but here is what 5 looks like for easy round numbers).
Think of it like drawing 5 cards one at a time.
Step-by-step logic
First card is a land:
17/40
There are 17 lands out of 40 cards.
Second card is also a land:
Now there are:
16 lands left
39 total cards left
16/39
Third card:
15/38
Fourth card:
14/37
Fifth card:
13/36
Now multiply them
Because all 5 events must happen:
(17/40)×(16/39)×(15/38)×(14/37)×(13/36)
Why multiply?
Because:
Probability of A AND B AND C AND D AND E
= multiply each step together.That equals:
≈0.0094≈ 0.0094≈0.0094
Which is:
0.94%
That’s the chance that one specific 5-card stretch is all lands.
Just to be clear, this happens with an average of 6.1 lands drawn back to back over a course of 100 games 57% of the time. (I started recording late last year just to matter of fact.) Here are the odds that I had my specifically designed probability computer system put together just to be certain.
Step 1 — What is the true probability of 6 lands in a row?
Earlier we established:
For a 40-card deck with 17 lands:
Probability of at least one 6-land streak somewhere in the deck ≈ 1%
That means:
p=0.01p = 0.01p=0.01
So in any given game, you have about a 1 in 100 chance of seeing a 6-land streak.
Step 2 — What would 57% mean?
57% over 100 games means:
57 games out of 100
But if the true probability is 1%, then over 100 games you would expect:
100 × 0.01= 1 game
So the expectation is:
Expected = 1 game
Claimed = 57 games
That’s 57× higher than mathematically expected.
Step 3 — What are the odds of that happening naturally?
This is a binomial probability problem.
We ask:
If each game has a 1% chance of a 6-land streak, what’s the probability of getting 57 or more successes out of 100 games?
That probability is effectively:
≈10−100 or smaller≈ 10^{-100} { or smaller}≈10−100 or smaller
To put that in perspective:
Odds of winning the Powerball jackpot: ~1 in 292 million
This event: far, far, far less likely than winning the lottery multiple times in a row
In practical terms:
The probability is effectively zero.
Not “very unlikely.”
Not “rare.”
Mathematically indistinguishable from impossible.Step 4 — The “Average of 6.1 Lands in a Row” Claim
This makes it even more impossible.
Why?
Because:
7-land streak odds ≈ 0.3%
8-land streak odds are even smaller
9-land streak odds are microscopic
To average 6.1 lands in a row 57% of games means you are regularly hitting 6, 7, maybe 8 land streaks constantly.
That violates what’s called the law of large numbers.
With a fair shuffle, over time results converge toward expected probability — not explode away from it.
Step 5 — Could It Happen Without Manipulation?
Only if:
The deck does NOT actually contain 17 lands.
The shuffle is not random.
The data collection is biased (memory bias).
The sample size is misreported.
There is a physical issue (clumping from insufficient shuffling).
But under:
True randomness
Proper shuffle
17 lands
It is not statistically plausible.
This will be posted for everyone of your customers who have this issue to see. I hope that you can figure it out before the uproar gets too loud for you to handle.
-Anonymous
An error occurred while saving the comment
opietaylor93#81905
commented
Hello, I have a mathematics and probability masters degree and find this sort of stuff fascinating. I work with major platforms and machinery that specializes in randomizing, odds and probability. While most stuff does seem random and by “chance”; complex calculations allow us to understand that with enough rinse and repeat (for laymen's terms) proves that there is always some sort of pattern associated with numbers. For example, I have done some calculations that are correct (you can check yourself) that prove that the shuffling system in MTG Arena is not truly a chance factor. Here is what I found.
I have played hundreds of matches in Arena, paid hundreds of dollars for gems to play in limited events and been a great reoccurring customer to MTGA. Here is the equation I used which is tried and true and also correct without any errors:
This applies to any stretch of lands you pull off the top with or without a shuffle, The math stays the same. I personally experience this problem in about 45-60% (this is out of 100 games at a time that I studied) of my games which should be enough proof that this is obviously a money grab via Wizards of the Coast.
First we calculate the odds that 5 specific consecutive cards are all lands. (My ratio is 6.1 lands 57% of the time but here is what 5 looks like for easy round numbers).
Think of it like drawing 5 cards one at a time.
Step-by-step logic
First card is a land:
17/40
There are 17 lands out of 40 cards.
Second card is also a land:
Now there are:
16 lands left
39 total cards left
16/39
Third card:
15/38
Fourth card:
14/37
Fifth card:
13/36
Now multiply them
Because all 5 events must happen:
(17/40)×(16/39)×(15/38)×(14/37)×(13/36)
Why multiply?
Because:
Probability of A AND B AND C AND D AND E
= multiply each step together.That equals:
≈0.0094≈ 0.0094≈0.0094
Which is:
0.94%
That’s the chance that one specific 5-card stretch is all lands.
Just to be clear, this happens with an average of 6.1 lands drawn back to back over a course of 100 games 57% of the time. (I started recording late last year just to matter of fact.) Here are the odds that I had my specifically designed probability computer system put together just to be certain.
Step 1 — What is the true probability of 6 lands in a row?
Earlier we established:
For a 40-card deck with 17 lands:
Probability of at least one 6-land streak somewhere in the deck ≈ 1%
That means:
p=0.01p = 0.01p=0.01
So in any given game, you have about a 1 in 100 chance of seeing a 6-land streak.
Step 2 — What would 57% mean?
57% over 100 games means:
57 games out of 100
But if the true probability is 1%, then over 100 games you would expect:
100 × 0.01= 1 game
So the expectation is:
Expected = 1 game
Claimed = 57 games
That’s 57× higher than mathematically expected.
Step 3 — What are the odds of that happening naturally?
This is a binomial probability problem.
We ask:
If each game has a 1% chance of a 6-land streak, what’s the probability of getting 57 or more successes out of 100 games?
That probability is effectively:
≈10−100 or smaller≈ 10^{-100} { or smaller}≈10−100 or smaller
To put that in perspective:
Odds of winning the Powerball jackpot: ~1 in 292 million
This event: far, far, far less likely than winning the lottery multiple times in a row
In practical terms:
The probability is effectively zero.
Not “very unlikely.”
Not “rare.”
Mathematically indistinguishable from impossible.Step 4 — The “Average of 6.1 Lands in a Row” Claim
This makes it even more impossible.
Why?
Because:
7-land streak odds ≈ 0.3%
8-land streak odds are even smaller
9-land streak odds are microscopic
To average 6.1 lands in a row 57% of games means you are regularly hitting 6, 7, maybe 8 land streaks constantly.
That violates what’s called the law of large numbers.
With a fair shuffle, over time results converge toward expected probability — not explode away from it.
Step 5 — Could It Happen Without Manipulation?
Only if:
The deck does NOT actually contain 17 lands.
The shuffle is not random.
The data collection is biased (memory bias).
The sample size is misreported.
There is a physical issue (clumping from insufficient shuffling).
But under:
True randomness
Proper shuffle
17 lands
It is not statistically plausible.
This will be posted for everyone of your customers who have this issue to see. I hope that you can figure it out before the uproar gets too loud for you to handle.
-Anonymous
-
Hello, I have a mathematics and probability masters degree and find this sort of stuff fascinating. I work with major platforms and machinery that specializes in randomizing, odds and probability. While most stuff does seem random and by “chance”; complex calculations allow us to understand that with enough rinse and repeat (for laymen's terms) proves that there is always some sort of pattern associated with numbers. For example, I have done some calculations that are correct (you can check yourself) that prove that the shuffling system in MTG Arena is not truly a chance factor. Here is what I found.
I have played hundreds of matches in Arena, paid hundreds of dollars for gems to play in limited events and been a great reoccurring customer to MTGA. Here is the equation I used which is tried and true and also correct without any errors:
This applies to any stretch of lands you pull off the top with or without a shuffle, The math stays the same. I personally experience this problem in about 45-60% (this is out of 100 games at a time that I studied) of my games which should be enough proof that this is obviously a money grab via Wizards of the Coast.
First we calculate the odds that 5 specific consecutive cards are all lands. (My ratio is 6.1 lands 57% of the time but here is what 5 looks like for easy round numbers).
Think of it like drawing 5 cards one at a time.
Step-by-step logic
First card is a land:
17/40
There are 17 lands out of 40 cards.
Second card is also a land:
Now there are:
16 lands left
39 total cards left
16/39
Third card:
15/38
Fourth card:
14/37
Fifth card:
13/36
Now multiply them
Because all 5 events must happen:
(17/40)×(16/39)×(15/38)×(14/37)×(13/36)
Why multiply?
Because:
That equals:
≈0.0094≈ 0.0094≈0.0094
Which is:
0.94%
That’s the chance that one specific 5-card stretch is all lands.
Just to be clear, this happens with an average of 6.1 lands drawn back to back over a course of 100 games 57% of the time. (I started recording late last year just to matter of fact.) Here are the odds that I had my specifically designed probability computer system put together just to be certain.
Step 1 — What is the true probability of 6 lands in a row?
Earlier we established:
For a 40-card deck with 17 lands:
Probability of at least one 6-land streak somewhere in the deck ≈ 1%
That means:
p=0.01p = 0.01p=0.01
So in any given game, you have about a 1 in 100 chance of seeing a 6-land streak.
Step 2 — What would 57% mean?
57% over 100 games means:
57 games out of 100
But if the true probability is 1%, then over 100 games you would expect:
100 × 0.01= 1 game
So the expectation is:
Expected = 1 game
Claimed = 57 games
That’s 57× higher than mathematically expected.
Step 3 — What are the odds of that happening naturally?
This is a binomial probability problem.
We ask:
That probability is effectively:
≈10−100 or smaller≈ 10^{-100} { or smaller}≈10−100 or smaller
To put that in perspective:
Odds of winning the Powerball jackpot: ~1 in 292 million
This event: far, far, far less likely than winning the lottery multiple times in a row
In practical terms:
The probability is effectively zero.
Not “very unlikely.”
Not “rare.”
Mathematically indistinguishable from impossible.
Step 4 — The “Average of 6.1 Lands in a Row” Claim
This makes it even more impossible.
Why?
Because:
7-land streak odds ≈ 0.3%
8-land streak odds are even smaller
9-land streak odds are microscopic
To average 6.1 lands in a row 57% of games means you are regularly hitting 6, 7, maybe 8 land streaks constantly.
That violates what’s called the law of large numbers.
With a fair shuffle, over time results converge toward expected probability — not explode away from it.
Step 5 — Could It Happen Without Manipulation?
Only if:
The deck does NOT actually contain 17 lands.
The shuffle is not random.
The data collection is biased (memory bias).
The sample size is misreported.
There is a physical issue (clumping from insufficient shuffling).
But under:
True randomness
Proper shuffle
17 lands
It is not statistically plausible.
This will be posted for everyone of your customers who have this issue to see. I hope that you can figure it out before the uproar gets too loud for you to handle.
-Anonymous